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What will be the output of the program? #include<stdio.h> int main() { int x=12, y=7, z; z = x!=4 || y == 2; printf("z=%d\n", z); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> int main() { int x=12, y=7, z; z = x!=4 || y == 2; printf("z=%d\n", z); return 0; }





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  • By: guest on 01 Jun 2017 06.01 pm
    Step 1: int x=12, y=7, z; here variable x, y and z are declared as an integer and variable x and y are initialized to 12, 7 respectively. Step 2: z = x!=4 || y == 2;
    becomes z = 12!=4 || 7 == 2;
    then z = (condition true) || (condition false); Hence it returns 1. So the value of z=1. Step 3: printf("z=%d\n", z); Hence the output of the program is "z=1".
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