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What will be the output of the program? #include<stdio.h> int main() { int x=4, y, z; y = --x; z = x--; printf("%d, %d, %d\n", x, y, z); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> int main() { int x=4, y, z; y = --x; z = x--; printf("%d, %d, %d\n", x, y, z); return 0; }





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  • By: guest on 01 Jun 2017 06.01 pm
    Step 1: int x=4, y, z; here variable x, y, z are declared as an integer type and variable x is initialized to 4.
    Step 2: y = --x; becomes y = 3; because (--x) is pre-decrement operator.
    Step 3: z = x--; becomes z = 3;. In the next step variable x becomes 2, because (x--) is post-decrement operator.
    Step 4: printf("%d, %d, %d\n", x, y, z); Hence it prints "2, 3, 3".
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