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1. What will be the output of the program? public class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (RuntimeException ex) / Line 10 / { System.out.print("B"); } catch (Exception ex1) { System.out.print("C"); } finally { System.out.print("D"); } System.out.print("E"); } public static void badMethod() { throw new RuntimeException(); } }





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  • By: guest on 02 Jun 2017 01.26 am
    A Run time exception is thrown and caught in the catch statement on line 10. All the code after the finally statement is run because the exception has been caught.
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